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 December 14th, 2012, 04:49 PM #1 Member   Joined: Dec 2012 Posts: 30 Thanks: 0 Variation d varies directly with the cube of w and inversely with p; use k as the constant of proportionality. Can anyone help me solve this?
 December 14th, 2012, 04:59 PM #2 Member   Joined: Dec 2012 Posts: 30 Thanks: 0 Re: Variation Does anyone know where I would start? What should I do first?
 December 14th, 2012, 05:11 PM #3 Senior Member     Joined: Jul 2012 From: DFW Area Posts: 614 Thanks: 83 Math Focus: Electrical Engineering Applications Re: VAriation I'm not sure what the question is.
 December 14th, 2012, 05:13 PM #4 Member   Joined: Dec 2012 Posts: 30 Thanks: 0 Re: Variation They are saying write as an equation expressing the relationship d varies directly with the cube of w and inversely with p; use k as the constant of proportionality.
 December 14th, 2012, 05:29 PM #5 Senior Member     Joined: Jul 2012 From: DFW Area Posts: 614 Thanks: 83 Math Focus: Electrical Engineering Applications Re: Variation $d=k \cdot \frac{w^3}{p}$ I'm not sure how much you know or don't know, so bear with me if I say things that you are already aware of. First, the 3 superscript on the w means it is cubed and since d varies directly with w cubed, w cubed is in the numerator on the other side of the equals sign. On the other hand, since d varies inversely with p, then p is in the denominator. The constant of proportionality k is assumed to be in the numerator. If you have any questions, please reply.
 December 14th, 2012, 05:38 PM #6 Member   Joined: Dec 2012 Posts: 30 Thanks: 0 Re: Variation Ok thank you, very well explained. Are you copying your symbols from another website if you don't mind my asking?
 December 14th, 2012, 05:45 PM #7 Senior Member     Joined: Jul 2012 From: DFW Area Posts: 614 Thanks: 83 Math Focus: Electrical Engineering Applications Re: Variation No, I am using $\LaTeX$ You can quote my replies to see examples. There are also many online guides.

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