My Math Forum Complex numbers
 User Name Remember Me? Password

 Algebra Pre-Algebra and Basic Algebra Math Forum

December 14th, 2012, 09:22 AM   #1
Newbie

Joined: Dec 2012

Posts: 28
Thanks: 0

Complex numbers

Help about complex number (attachment)
Attached Images
 image.jpg (88.1 KB, 119 views)

 December 14th, 2012, 11:41 AM #2 Math Team   Joined: Nov 2010 From: Greece, Thessaloniki Posts: 1,990 Thanks: 133 Math Focus: pre pre pre pre pre pre pre pre pre pre pre pre calculus Re: Complex numbers [color=#000000]From the identity $z+\overline{z}=2\Re e(z)$, $\frac{z+\overline{z}}{2z+3}=\frac{-1}{-1+i+3}=-\frac{1}{2+i}=-\frac{2-i}{5}=-\frac{1}{5}(2-i)$ .[/color]
December 14th, 2012, 12:48 PM   #3
Global Moderator

Joined: May 2007

Posts: 6,805
Thanks: 716

Re: Complex numbers

Quote:
 Originally Posted by ZardoZ [color=#000000]From the identity $z+\overline{z}=\Re e(z)$, $\frac{z+\overline{z}}{2z+3}=\frac{-\frac{1}{2}}{-1+i+3}=-\frac{1}{2}\frac{1}{2+i}=-\frac{1}{2}\cdot\frac{2-i}{5}=-\frac{1}{10}\left(2-i)$ .[/color]
$z+\overline{z}=\Re e(z)$ should be $z+\overline{z}=2\Re e(z)$

 December 14th, 2012, 08:48 PM #4 Newbie   Joined: Dec 2012 Posts: 28 Thanks: 0 Re: Complex numbers Thank you ! But can you do it step by step, how did you get -1?
December 15th, 2012, 11:58 AM   #5
Global Moderator

Joined: May 2007

Posts: 6,805
Thanks: 716

Re: Complex numbers

Quote:
 Originally Posted by Miran977 Thank you ! But can you do it step by step, how did you get -1?
Re(z) = -1/2, 2Re(z) = -1

 Tags complex, numbers

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post jonas Complex Analysis 2 October 13th, 2014 03:03 PM Miran977 Algebra 5 December 16th, 2012 01:03 PM Miran977 Algebra 14 December 16th, 2012 02:58 AM Tutu Algebra 11 June 26th, 2012 01:36 PM jakeward123 Complex Analysis 9 February 8th, 2011 01:49 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top