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December 7th, 2012, 07:28 AM   #1
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circle

[color=#008000]Dear All!
If we have:

http://www.mathsisfun.com/algebra/circle-equations.html

does anyone have the good pic so that we can be sure that we MIGHT use a=1, b=2 and c=3?
Thanks!
[/color]
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December 7th, 2012, 08:29 AM   #2
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Re: circle

[color=#0000FF]Well, I think we can choose a, b and c as we want, but we CAN'T choose A, B and C, this HAS to be calculated...[/color]
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December 7th, 2012, 08:43 AM   #3
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Re: circle

a=1, b=2, c=3 CANNOT be a triangle.
What is your question?
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December 7th, 2012, 01:24 PM   #4
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Re: circle

[color=#008000](x-a)^2+(y-b)^2=c^2, can be a triangle.
x^2+y^2+Ax+By+c=0 has just Aa, Bb and Cc

Have a look at the pic I linked!
Sides of the triangle are not a, b, c but (x-a), (y-b), c
.[/color]
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December 7th, 2012, 03:21 PM   #5
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As (a, b) specifies where the circle is, a and b can have any values. It's clear that c = r, so c can have any positive value. If you had c = 0, the "circle" would be just the single point (a, b). The linked site already has good pictures.
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