December 7th, 2012, 07:28 AM  #1 
Senior Member Joined: Oct 2012 Posts: 460 Thanks: 0  circle
[color=#008000]Dear All! If we have: http://www.mathsisfun.com/algebra/circleequations.html does anyone have the good pic so that we can be sure that we MIGHT use a=1, b=2 and c=3? Thanks! [/color] 
December 7th, 2012, 08:29 AM  #2 
Senior Member Joined: Oct 2012 Posts: 460 Thanks: 0  Re: circle
[color=#0000FF]Well, I think we can choose a, b and c as we want, but we CAN'T choose A, B and C, this HAS to be calculated...[/color]

December 7th, 2012, 08:43 AM  #3 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1039  Re: circle
a=1, b=2, c=3 CANNOT be a triangle. What is your question? 
December 7th, 2012, 01:24 PM  #4 
Senior Member Joined: Oct 2012 Posts: 460 Thanks: 0  Re: circle
[color=#008000](xa)^2+(yb)^2=c^2, can be a triangle. x^2+y^2+Ax+By+c=0 has just Aa, Bb and Cc Have a look at the pic I linked! Sides of the triangle are not a, b, c but (xa), (yb), c.[/color] 
December 7th, 2012, 03:21 PM  #5 
Global Moderator Joined: Dec 2006 Posts: 21,020 Thanks: 2256 
As (a, b) specifies where the circle is, a and b can have any values. It's clear that c = r, so c can have any positive value. If you had c = 0, the "circle" would be just the single point (a, b). The linked site already has good pictures.


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