My Math Forum Complex number and polar form

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 June 15th, 2008, 04:15 AM #1 Newbie   Joined: May 2008 Posts: 29 Thanks: 0 Complex number and polar form Hello! in some engineering textbook, i have: -j0.02/_-50 = (1/_-90)(0.02/_-50) i dont understand this transition... where do they get (1/_-90) from? i know that -j = 1/j, but that doesnt help me much in understanding of this transition... thanks in advance!
 June 15th, 2008, 12:25 PM #2 Global Moderator   Joined: Dec 2006 Posts: 20,484 Thanks: 2041 Any complex number can be given in (r, ?) form (where r cos(?) is the real part and r sin(?) is the imaginary part). The above notation seems to be giving the value of r then "/_" and then ? in degrees (since "`" appears to mean degrees). Does that help?
 June 22nd, 2008, 04:01 PM #3 Senior Member   Joined: Dec 2006 Posts: 1,111 Thanks: 0 Re: Complex number and polar form All complex numbers are also two-dimensional vectors. Thus all the rules for adding, subtracting, scalar multiplying, switching from polar to rectangular forms and vice versa, etc., are applicable to complex numbers just as they are to any other vector, such as velocity vectors. I don't know what you are dealing with here, but it seems like you might be working with AC electricity phasors. Phasors are just complex numbers, and as such can also be represented as vectors, with all the properties of vectors being applicable to them. Look up the properties of vectors in a physics book, and they will also apply to all complex numbers as well.

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