My Math Forum Exponent help

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 January 20th, 2016, 05:07 PM #1 Member   Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3 Exponent help Hi I have this one math problem and it's really hard. I got an answer but it's probably wrong. Can someone please solve it and tell me what you get. I want to compare it to my answer Thanks. Here it is: (2(squared) a(to the -1 power) b(to the -3 power) c) the -2 power divided by 8( to the -1 power) ab( to the -5 power) c(to the 0 power) *In the first line, all the terms from 2 to c are in parentheses and the -2 exponent is on the outside of the parentheses
 January 20th, 2016, 05:34 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond Do you mean $\displaystyle \dfrac{\left(2^2\cdot a^{-1}\cdot b^{-3}\cdot c\right)^{-2}}{8^{-1}\cdot(a\cdot b)^{-5} \cdot c^0}$ ? Last edited by skipjack; January 20th, 2016 at 05:49 PM.
 January 20th, 2016, 05:38 PM #3 Member   Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3 No, sorry, it's a little different; how did you type the exponents? The exponent the a and b below the fraction bar are not in the same parentheses but other than that, yes that is what I meant. Please solve if you get a chance. I really appreciate your help. Thanks. Last edited by skipjack; January 20th, 2016 at 05:51 PM.
 January 20th, 2016, 05:44 PM #4 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond I used LaTeX. Typing $2^{2}$ gives $\displaystyle 2^2$. Typing $\dfrac{4}{3}$ gives $\displaystyle \dfrac{4}{3}$. Typing $\dfrac{4}{3}+2^{2}$ gives $\displaystyle \dfrac{4}{3}+2^{2}$.
 January 20th, 2016, 05:51 PM #5 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond $\displaystyle \dfrac{\left(2^2\cdot a^{-1}\cdot b^{-3}\right)^{-2}}{8^{-1}\cdot a\cdot b^{-5}\cdot c^0}$ Like that? I get $\displaystyle \dfrac12ab^{11}$.
 January 20th, 2016, 05:56 PM #6 Member   Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3 Thank you so much. The only thing was you forgot the c in the parentheses above the fraction bar but that's okay. Thank you so much. I really appreciate it Thanks from greg1313
January 20th, 2016, 05:57 PM   #7
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Quote:
 Originally Posted by hhmathgeek I got an answer . . .

January 20th, 2016, 06:00 PM   #8
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Quote:
 Originally Posted by hhmathgeek The only thing was you forgot the c in the parentheses above the fraction bar...
Yep.

$\displaystyle \dfrac{\left(2^2\cdot a^{-1}\cdot b^{-3}\cdot c\right)^{-2}}{8^{-1}\cdot a\cdot b^{-5}\cdot c^0}=\dfrac12ab^{11}c^{-2}=\dfrac{ab^{11}}{2c^2}$

 January 20th, 2016, 06:03 PM #9 Member   Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3 Thank you so much. My answer was sort of similar but not quite
 January 20th, 2016, 06:05 PM #10 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond Why don't you post your work? We can help you better if you do that.

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