January 20th, 2016, 05:07 PM  #1 
Member Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3  Exponent help
Hi I have this one math problem and it's really hard. I got an answer but it's probably wrong. Can someone please solve it and tell me what you get. I want to compare it to my answer Thanks. Here it is: (2(squared) a(to the 1 power) b(to the 3 power) c) the 2 power divided by 8( to the 1 power) ab( to the 5 power) c(to the 0 power) *In the first line, all the terms from 2 to c are in parentheses and the 2 exponent is on the outside of the parentheses 
January 20th, 2016, 05:34 PM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond 
Do you mean $\displaystyle \dfrac{\left(2^2\cdot a^{1}\cdot b^{3}\cdot c\right)^{2}}{8^{1}\cdot(a\cdot b)^{5} \cdot c^0}$ ? Last edited by skipjack; January 20th, 2016 at 05:49 PM. 
January 20th, 2016, 05:38 PM  #3 
Member Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3 
No, sorry, it's a little different; how did you type the exponents? The exponent the a and b below the fraction bar are not in the same parentheses but other than that, yes that is what I meant. Please solve if you get a chance. I really appreciate your help. Thanks. Last edited by skipjack; January 20th, 2016 at 05:51 PM. 
January 20th, 2016, 05:44 PM  #4 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond 
I used LaTeX. Typing [math]2^{2}[/math] gives $\displaystyle 2^2$. Typing [math]\dfrac{4}{3}[/math] gives $\displaystyle \dfrac{4}{3}$. Typing [math]\dfrac{4}{3}+2^{2}[/math] gives $\displaystyle \dfrac{4}{3}+2^{2}$. 
January 20th, 2016, 05:51 PM  #5 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond 
$\displaystyle \dfrac{\left(2^2\cdot a^{1}\cdot b^{3}\right)^{2}}{8^{1}\cdot a\cdot b^{5}\cdot c^0}$ Like that? I get $\displaystyle \dfrac12ab^{11}$. 
January 20th, 2016, 05:56 PM  #6 
Member Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3 
Thank you so much. The only thing was you forgot the c in the parentheses above the fraction bar but that's okay. Thank you so much. I really appreciate it 
January 20th, 2016, 05:57 PM  #7 
Global Moderator Joined: Dec 2006 Posts: 20,933 Thanks: 2207  
January 20th, 2016, 06:00 PM  #8 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond  
January 20th, 2016, 06:03 PM  #9 
Member Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3 
Thank you so much. My answer was sort of similar but not quite 
January 20th, 2016, 06:05 PM  #10 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond 
Why don't you post your work? We can help you better if you do that.


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