Exponent help Hi :) I have this one math problem and it's really hard. I got an answer but it's probably wrong. Can someone please solve it and tell me what you get. I want to compare it to my answer :) Thanks. Here it is: (2(squared) a(to the 1 power) b(to the 3 power) c) the 2 power divided by 8( to the 1 power) ab( to the 5 power) c(to the 0 power) *In the first line, all the terms from 2 to c are in parentheses and the 2 exponent is on the outside of the parentheses 
Do you mean $\displaystyle \dfrac{\left(2^2\cdot a^{1}\cdot b^{3}\cdot c\right)^{2}}{8^{1}\cdot(a\cdot b)^{5} \cdot c^0}$ ? 
No, sorry, it's a little different; how did you type the exponents? The exponent the a and b below the fraction bar are not in the same parentheses but other than that, yes :) that is what I meant. Please solve :) if you get a chance. I really appreciate your help. Thanks. 
I used LaTeX. Typing [math]2^{2}[/math] gives $\displaystyle 2^2$. Typing [math]\dfrac{4}{3}[/math] gives $\displaystyle \dfrac{4}{3}$. Typing [math]\dfrac{4}{3}+2^{2}[/math] gives $\displaystyle \dfrac{4}{3}+2^{2}$. 
$\displaystyle \dfrac{\left(2^2\cdot a^{1}\cdot b^{3}\right)^{2}}{8^{1}\cdot a\cdot b^{5}\cdot c^0}$ Like that? I get $\displaystyle \dfrac12ab^{11}$. 
Thank you so much. The only thing was you forgot the c in the parentheses above the fraction bar but that's okay. Thank you so much. I really appreciate it :) 
Quote:

Quote:
$\displaystyle \dfrac{\left(2^2\cdot a^{1}\cdot b^{3}\cdot c\right)^{2}}{8^{1}\cdot a\cdot b^{5}\cdot c^0}=\dfrac12ab^{11}c^{2}=\dfrac{ab^{11}}{2c^2}$ 
Thank you so much. My answer was sort of similar but not quite :) 
Why don't you post your work? We can help you better if you do that. 
All times are GMT 8. The time now is 12:20 PM. 
Copyright © 2019 My Math Forum. All rights reserved.