January 20th, 2016, 06:17 PM  #11 
Member Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3 
I'll be here for hours typing my work but my final answer was a(squared) b( to the 11th power) over 2 c(squared) a

January 20th, 2016, 06:31 PM  #12 
Member Joined: Sep 2015 From: Philadelphia Posts: 36 Thanks: 3 
I just figured out my mistake. It was in my subtraction. It's amazing how one little thing can affect the whole problem. Thanks again 
January 21st, 2016, 05:18 AM  #13  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,414 Thanks: 1024  Quote:
(a^2 * b^11) / (2 * c^2 * a) That's not really incorrect: just needs one further simplification: (a * b^11) / (2 * c^2) ...which you say you got...so all's well  
January 21st, 2016, 07:16 PM  #14 
Senior Member Joined: May 2015 From: Varanasi Posts: 110 Thanks: 5 Math Focus: Calculus 
Well i think that is quiet simple just subtract the exponents of same variable below fraction from the exponents of variable above fraction. Thats the central idea.


Tags 
exponent 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Where did this exponent come from?  The_Ys_Guy  Algebra  3  May 1st, 2015 07:21 PM 
Exponent  bml1105  Algebra  12  July 27th, 2014 11:40 AM 
Exponent  Thinkhigh  Calculus  3  March 2nd, 2012 06:42 AM 
When it comes to solving x with an exponent  dthomas86  Algebra  7  January 2nd, 2012 12:24 AM 
Mudulo exponent  alfonso1  Number Theory  17  August 7th, 2007 09:03 AM 