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January 30th, 2007, 03:56 AM  #1 
Senior Member Joined: Dec 2006 From: New Jersey Posts: 378 Thanks: 1  Right Circular Cone Problem
The volume V of a right circular cone is V = (1/3)(pi)(r^2)(h). If the height is TWICE the radius, express the volume V as a function of r. NOTE: What is a more simple way to say: "...express the volume V as a function of r." 
January 30th, 2007, 04:17 AM  #2 
Senior Member Joined: Dec 2006 Posts: 1,111 Thanks: 0 
This is a supereasy problem. Since we are told that h=2r, and we know that: V = (1/3)(pi)(r^2)(h) We can just substitue 2r for h and go from there: V = (1/3)(pi)(r^2)(2r) V = (2/3)(pi)(r^3) 
January 30th, 2007, 12:02 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 18,444 Thanks: 1462 
The wording is fairly typical (though not ideal) and can't really be simplified. It means that you have to obtain a definition of V in terms of r alone, as distinct from in terms of r and h. Strictly speaking, you should also state what value r may have (in this case, any nonnegative real value), since the formal definition of a function includes specifying its domain. 
January 30th, 2007, 02:04 PM  #4 
Senior Member Joined: Dec 2006 From: New Jersey Posts: 378 Thanks: 1  ok
It is just plug and chug, right?


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