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November 9th, 2012, 11:06 AM   #1
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How to predict the death rate in 1993 ?

The shows the age-adjusted death rates (per 100,000 population) for heart disease in a certain country.

,,,,,,,Year|1970|1980|1990|1995|1997
DeathRate|253.5|197.4|153.7|135.6|129.0

Use the first and last data points to find an exponential function of the form f(t)=y0b^t where t is the time in years and t=0 in 1970. Then use the model to predict the death rate in 1993.
----------------------
f(0)=253.5
f(27)=129.0
y0b^0=253.5
y0=253.5
-
f(27)=129.0
253.5b^27=129.0
b^27=0.5089
b=0.9753 <<<<How do we take 27th roots on both sides Please explain how do we get this answer.
-
f(t) =253.5(0.9753)^23
=143

Thanks.
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November 9th, 2012, 11:08 AM   #2
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Re: How to predict the death rate in 1993 ?

The table shows****
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November 9th, 2012, 11:19 AM   #3
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Re: How to predict the death rate in 1993 ?

Use your calculator to get the 27th root.
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November 9th, 2012, 11:33 AM   #4
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Re: How to predict the death rate in 1993 ?

Do you think I didn't?
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November 9th, 2012, 11:41 AM   #5
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Re: How to predict the death rate in 1993 ?

You asked how to obtain the root, and I told you. I have no idea what you have tried or not, but it is easy to get using a calculator, so I assumed since you are asking, you did not try this.

I enter into my calculator:

(.5089)^(1/27)

and it gives:

.97529171561
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November 9th, 2012, 11:49 AM   #6
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Re: How to predict the death rate in 1993 ?

Thanks that helped.
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