My Math Forum System of equations?

 Algebra Pre-Algebra and Basic Algebra Math Forum

 October 21st, 2012, 12:32 PM #1 Newbie   Joined: Oct 2012 Posts: 2 Thanks: 0 System of equations? I hope this is the correct place to post this. I have 4 equations with 4 unknowns. Let's assume the lower case letters represent different numbers that are known constants. A = B/s B = C/t C = D/u A + B + C + D = 10 Can anyone give me some hints on how to solve this? Thanks!
October 21st, 2012, 12:57 PM   #2
Math Team

Joined: Oct 2011

Posts: 13,638
Thanks: 954

Re: System of equations?

Quote:
 Originally Posted by wyckedjester I have 4 equations with 4 unknowns. Let's assume the lower case letters represent different numbers that are known constants. A = B/s B = C/t C = D/u A + B + C + D = 10 Can anyone give me some hints on how to solve this? Thanks!
I may be missing something...but problem makes little sense:
just get any 4 numbers that equal 10: as example, 1,2,3,4: A=1, B=2, C=3, D=4.

A = B/s : s = B/A = 2/1 = 2
B = C/t : t = C/B = 3/2
C = D/u : u = D/C = 4/3

October 21st, 2012, 01:44 PM   #3
Global Moderator

Joined: May 2007

Posts: 6,642
Thanks: 627

Re: System of equations?

Quote:
 Originally Posted by wyckedjester I hope this is the correct place to post this. I have 4 equations with 4 unknowns. Let's assume the lower case letters represent different numbers that are known constants. A = B/s B = C/t C = D/u A + B + C + D = 10 Can anyone give me some hints on how to solve this? Thanks!
C=D/u
B=C/t=D/(ut)
A=B/s=D/(stu)

D[1 + 1/u + 1/(ut) + 1/(stu)] = 10

I assume you can go from here.

October 22nd, 2012, 01:16 AM   #4
Newbie

Joined: Oct 2012

Posts: 2
Thanks: 0

Re: System of equations?

Quote:
Originally Posted by mathman
Quote:
 Originally Posted by wyckedjester I hope this is the correct place to post this. I have 4 equations with 4 unknowns. Let's assume the lower case letters represent different numbers that are known constants. A = B/s B = C/t C = D/u A + B + C + D = 10 Can anyone give me some hints on how to solve this? Thanks!
C=D/u
B=C/t=D/(ut)
A=B/s=D/(stu)

D[1 + 1/u + 1/(ut) + 1/(stu)] = 10

I assume you can go from here.
Thanks! That worked perfectly! Never would have thought to do it that way...

 October 22nd, 2012, 05:31 AM #5 Global Moderator   Joined: Dec 2006 Posts: 19,992 Thanks: 1855 Any way that you've been taught (or can find) to solve simultaneous linear equations would have worked.

 Tags equations, system

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post alenov Algebra 4 May 17th, 2013 06:09 AM rs_lyly2009 Algebra 6 May 4th, 2013 05:23 PM ZeusTheMunja Linear Algebra 20 January 25th, 2013 06:52 AM zana93 Algebra 1 July 12th, 2012 11:02 AM aviation officer Algebra 4 March 8th, 2011 11:08 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top