October 4th, 2012, 05:39 PM  #1 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,112 Thanks: 910  Cross Side! Code: (U) A (Z) D (Y) [M] B E (V) C (W) F (X) Of course: UV = VW = WX = XY = YZ = ZU = 4. The cue ball is at M. Minnesota Fats performs the following "trick shot": shoots cue ball at point A: ball continues in order to points B,C,D,E,F, then from F directly to side pocket Z. What is size of angle MAZ? Had fun with that...came up with ATAN(9/...prove me wrong (or right)! 
October 5th, 2012, 01:03 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,511 Thanks: 1743 
You are correct. The "vertical" and "horizontal" components of the path are 4 1/2 times the table width and twice the table length respectively, so angle MAZ = arctan(18/16) = arctan(9/.

October 6th, 2012, 09:48 AM  #3 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,112 Thanks: 910  Re: Cross Side!
Thanks Skip...took me a while to "digest" that ! Real cool 

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