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September 30th, 2012, 03:36 AM  #1 
Senior Member Joined: Sep 2012 Posts: 201 Thanks: 1  Similar triangles
I am having a bit of trouble finding the length of AD in the triangle that I have attached to the post. Could someone show how to go about this question. Question: The diagram shows two similar triangles ABC and BCD. BC=7cm, DC=5cm and angle BAD= angle CBD. Calculate length AD. I feel I should be to Pythagoras but as it is not a right hand triangle I have no idea where to start. 
September 30th, 2012, 04:36 AM  #2 
Math Team Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233  Re: Similar triangles
If the triangles are simillar then There is another possibility, AD = 0 , then ABC is exactly on top of DBC or vice versa. 

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