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September 21st, 2012, 03:52 AM   #1
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How do I find the 'Highest' and 'Lowest' point of the Circle

r=2
center= (-1,2)

(x+1)^2 + (y-2)^2 = 2

I was thinking I just take the radius and add it + or - on the Y axis from the center?

Is there any analytical way to do this? I really don't like graphing!

Thank a lot!
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September 21st, 2012, 04:15 AM   #2
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Re: How do I find the 'Highest' and 'Lowest' point of the Ci

Given the circle:



The points you desire are:



In other words, the "highest" point is r units directly above the center and the "lowest point is r units directly below the center.
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