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September 21st, 2012, 03:52 AM  #1 
Newbie Joined: Sep 2012 Posts: 15 Thanks: 0  How do I find the 'Highest' and 'Lowest' point of the Circle
r=2 center= (1,2) (x+1)^2 + (y2)^2 = 2 I was thinking I just take the radius and add it + or  on the Y axis from the center? Is there any analytical way to do this? I really don't like graphing! Thank a lot! 
September 21st, 2012, 04:15 AM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs  Re: How do I find the 'Highest' and 'Lowest' point of the Ci
Given the circle: The points you desire are: In other words, the "highest" point is r units directly above the center and the "lowest point is r units directly below the center. 

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