My Math Forum numeric entry problem with answer..but I think the answer is

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 September 14th, 2012, 09:12 PM #1 Newbie   Joined: May 2012 Posts: 23 Thanks: 0 numeric entry problem with answer..but I think the answer is wrong. Here is the question: Assume that 2x is a positive multiple of 5 and is greater than 5. If 2x + 1 < 100, how many values for x are possible? I said the answer would be 18, but the website I found the question and answer on says the answer is 17 http://www.west.net/~stewart/gre/practi ... ntry-4.htm The reasoning is that x must be greater than 5, but the problem says that 2x is greater than 5 NOT x. Can someone shed some light? Thanks!
 September 14th, 2012, 09:44 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs Re: numeric entry problem with answer..but I think the answe I agree with you, you would not eliminate 5, since 5<2·5.
 September 14th, 2012, 10:27 PM #3 Global Moderator   Joined: Dec 2006 Posts: 20,310 Thanks: 1978 As 5 < 2x < 99, 2x ? {10, 15, 20, 25, 30, 25, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95}. Hence 18 is correct.

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