My Math Forum Solve for 'x' (with 4 variables and 1 equation)

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 August 2nd, 2012, 04:07 AM #1 Member   Joined: Aug 2012 Posts: 88 Thanks: 0 Solve for 'x' (with 4 variables and 1 equation) $ac + bc= (a - c)(a + b) - xabcd^2$ I got it expanded to: $ac + bc = a^2 + ab - ac - bc - xabcd^2 0 = a^2 + ab - 2ac - bc - bd - xabcd^2$ I tried factoring different ways, but it didn't really get me anywhere, and there aren't any "special" factoring rules that I can identify immediately here. What should be my next step?
August 2nd, 2012, 04:15 AM   #2
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Re: Solve for 'x' (with 4 variables and 1 equation)

Quote:
 Originally Posted by PhizKid I got it expanded to . . . I tried factoring different ways . . .
You don't need to expand or factorize!

$ac+bc= (a-c)(a+b) - x \cdot abcd^2$

$\text{Subtract (a-c)(a+b) from both sides; } ac+bc - (a-c)(a+b)= x \cdot abcd^2$

$\text{Now divide both sides by abcd^2; } x= \frac{ac+bc - (a-c)(a+b)}{abcd^2}$

And you are done . . .

 August 2nd, 2012, 04:19 AM #3 Member   Joined: Aug 2012 Posts: 88 Thanks: 0 Re: Solve for 'x' (with 4 variables and 1 equation) Oh, I wrote down the problem incorrectly...
August 2nd, 2012, 08:50 AM   #4
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Re: Solve for 'x' (with 4 variables and 1 equation)

Quote:
 Originally Posted by PhizKid Oh, I wrote down the problem incorrectly...
Well, what is it CORRECTLY?

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