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July 14th, 2012, 02:35 PM   #1
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How to simplify algebraic expression





Which step have I done incorrectly?
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July 14th, 2012, 03:57 PM   #2
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Re: How to simplify algebraic expression

None, that is correct.
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July 14th, 2012, 07:54 PM   #3
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Re: How to simplify algebraic expression

Daigo, tired me out just looking at all that "writing"; on a timed test, you're in trouble!
I suggest you always look for short cuts; like:
a = x-2, b = x - 3 ; then expression shortens to:

1 / (b/a)^(1/2) * (b/a)^(-1/2) / 2 * 1 / a^2

= (b/a)^(-1/2) / [2a^2 * (b/a)^(1/2)]

= 1 / [2a^2 * (b/a)^(1/2) * (b/a)^(1/2)]

= 1 / [2a^2 * (b/a)]

= 1 / (2ab)

= 1 / [2(x-1)(x-3)]

Got that?

Btw, good job in getting correct answer...I'm impressed
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July 14th, 2012, 08:29 PM   #4
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Re: How to simplify algebraic expression

I would just write (doing a few simple operations mentally):



We see that the factor with the negative exponent will combine with the denominator of the first factor to give the rational expression there an exponent of 1, and then its denominator will cancel with the denominator of the 4th factor, leaving the end result.
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July 15th, 2012, 01:55 AM   #5
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Re: How to simplify algebraic expression











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