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 June 29th, 2012, 11:37 AM #1 Newbie   Joined: Jun 2012 From: Maldives Posts: 19 Thanks: 0 a vector question Given that $\vec{LM} \qquad=\ \binom{-3}{4}\ and\ \vec{MN} \qquad =\binom{-15}{p}$ find the following: (a) $\vec{|LM|} \qquad$ (b) a value for p if $\vec{|MN|} \qquad=\ 3\vec{|LM|}$
 June 29th, 2012, 12:02 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: a vector question I am assuming you mean: $\vec{LM}=\langle -3,4 \rangle$ $\vec{MN}=\langle -15,p \rangle$ Hence: a) $\|\vec{LM}\|=\sqrt{(-3)^2+4^2}=5$ b) $(-15)^2+p^2=$$3\cdot5$$^2$ $p=0$
 June 30th, 2012, 05:46 AM #3 Newbie   Joined: Jun 2012 From: Maldives Posts: 19 Thanks: 0 Re: a vector question Thank you ..

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