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 June 26th, 2012, 12:37 PM #1 Member   Joined: Apr 2012 Posts: 92 Thanks: 0 Polynomial help I would like to clarify one thing, in questions like, Find all third degree real polynomials with zeros of -1/2 and 1 -3i there's always this constant multiplied to the answer, such that the polynomial f(x) = a(answer). What and why is there a need for a constant to be multiplied? In a general polynomial like 3x^2+x+5, I don't see the need for existence of a constant, unless the constant is 1. Thank you! June 26th, 2012, 12:50 PM #2 Senior Member   Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Polynomial help Consider that the roots are not changed when multiplying the polynomial by a constant but the polynomial is changed. For instance: Yet, the two binomials have the same root. June 26th, 2012, 01:07 PM   #3
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Re: Polynomial help

Hello, Tutu!

Quote:
 I would like to clarify one thing, in questions like, Find all third degree real polynomials with zeros of -1/2 and 1 -3i. There's always this constant multiplied to the answer, such that the polynomial f(x) = a(answer). What and why is there a need for a constant to be multiplied? In a general polynomial like 3x^2+x+5, I don't see the need for existence of a constant, unless the constant is 1. Thank you!

[color=beige]. . [/color] June 26th, 2012, 01:10 PM #4 Member   Joined: Apr 2012 Posts: 92 Thanks: 0 Re: Polynomial help I see now, thank you thank you thank you! Tags polynomial Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post king.oslo Algebra 6 August 27th, 2013 06:11 AM alexmath Algebra 5 November 3rd, 2012 06:40 PM condemath Algebra 3 September 20th, 2011 08:34 PM unlimited Algebra 3 April 2nd, 2011 10:10 PM xcxc9 Linear Algebra 2 July 18th, 2010 04:18 PM

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