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June 21st, 2012, 06:43 AM  #1 
Member Joined: Sep 2011 Posts: 49 Thanks: 0  factorize the following expressions:
3ad^2 +2b + a + 6bd^2 I suppose it should look like that: a(3d^2+1) + 2b(3d^2+1) is that all? Second one: 12p^2+13p  4 ??????? 
June 21st, 2012, 06:58 AM  #2  
Global Moderator Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4  Re: factorize the following expressions: Quote:
(3d^2+1)(a+2b)  
June 21st, 2012, 07:19 AM  #3 
Member Joined: Sep 2011 Posts: 49 Thanks: 0  Re: factorize the following expressions:
thx

June 21st, 2012, 07:26 AM  #4  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 10,663 Thanks: 697  Re: factorize the following expressions: Quote:
(3p + 4)(4p  1)  
June 21st, 2012, 08:14 AM  #5 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,155 Thanks: 463 Math Focus: Calculus/ODEs  Re: factorize the following expressions:
For the second one, another approach: The product of the first and last coefficients is: We want two factors of 48 whose sum is the middle coefficient of 13, and those are 3, and 16. Since 12 is divisible by 3 and 4, we can get our 3 from 3(1) and our 16 from 4(4), so we have: 
June 21st, 2012, 09:07 AM  #6 
Member Joined: Sep 2011 Posts: 49 Thanks: 0  Re: factorize the following expressions:
thx


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