My Math Forum factorize the following expressions:

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 June 21st, 2012, 06:43 AM #1 Member   Joined: Sep 2011 Posts: 49 Thanks: 0 factorize the following expressions: 3ad^2 +2b + a + 6bd^2 I suppose it should look like that: a(3d^2+1) + 2b(3d^2+1) is that all? Second one: 12p^2+13p - 4 ???????
June 21st, 2012, 06:58 AM   #2
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Re: factorize the following expressions:

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 Originally Posted by luketapis 3ad^2 +2b + a + 6bd^2 I suppose it should look like that: a(3d^2+1) + 2b(3d^2+1) is that all?
From here, take out the common factor of 3d^2+1...
(3d^2+1)(a+2b)

 June 21st, 2012, 07:19 AM #3 Member   Joined: Sep 2011 Posts: 49 Thanks: 0 Re: factorize the following expressions: thx
June 21st, 2012, 07:26 AM   #4
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Re: factorize the following expressions:

Quote:
 Originally Posted by luketapis Second one: 12p^2+13p - 4 ???????
(3p + 4)(4p - 1)

 June 21st, 2012, 08:14 AM #5 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: factorize the following expressions: For the second one, another approach: $12p^2+13p-4$ The product of the first and last coefficients is: $12(-4)=-48$ We want two factors of -48 whose sum is the middle coefficient of 13, and those are -3, and 16. Since 12 is divisible by 3 and 4, we can get our -3 from 3(-1) and our 16 from 4(4), so we have: $(3p+4)(4p-1)$
 June 21st, 2012, 09:07 AM #6 Member   Joined: Sep 2011 Posts: 49 Thanks: 0 Re: factorize the following expressions: thx

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