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- - **20 balls for 4 people**
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20 balls for 4 peopleHello, can someone please help me with this one? In how many different ways 20 equal balls can be given to 4 people? - A situation where someone receives no ball IS valid. - All the 20 balls must be given. Thanks |

Re: 20 balls for 4 peopleConsider a string of 23 items, consisting of 20 balls, and 3 dividers. The three dividers divide your string up into 4 segments, one for each of the people. There is no a 1-to-1 correspondence between an arrangement of the items, and allocation of balls to the 4 people. So your question boils down to how many arrangements are there of 23 items of which 3 are of one type and 20 are of another type. Can you finish it from there? |

Re: 20 balls for 4 peopleQuote:
and I think this is number theory math! |

Re: 20 balls for 4 peopleHint: ways = (n+1)(n+2)(n+3) / k |

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