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June 18th, 2012, 08:50 AM  #1 
Newbie Joined: Jun 2012 Posts: 2 Thanks: 0  18 baby blocks.... need help.
So each block obviously has 6 sides with a different letter. All 18 blocks have the same 6 letters on them. They are randomly placed in a line, with 6 sets of 3...... ( 3 A's 3B's 3Cs 3Ds 3Es and 3Fs..... for the sake of the argument ) They are covered up and randomly put in a line of 18. What is the statistical chance that a person could pick 3 of the same letters on their first 3 picks? 
June 18th, 2012, 09:06 AM  #2 
Newbie Joined: Jun 2012 Posts: 2 Thanks: 0  Re: 18 baby blocks.... need help.
Thank you.... seeing it written like that really cleared it up.... I'm no math whiz, but just in my head I was thinking it was like a 10,000  1 shot.

June 18th, 2012, 09:07 AM  #3 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,406 Thanks: 859 Math Focus: Elementary mathematics and beyond  Re: 18 baby blocks.... need help. 
June 18th, 2012, 09:17 AM  #4 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,406 Thanks: 859 Math Focus: Elementary mathematics and beyond  Re: 18 baby blocks.... need help.
Sorry about the misplaced post  I made an error editing.

June 18th, 2012, 02:11 PM  #5  
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,406 Thanks: 859 Math Focus: Elementary mathematics and beyond  Re: 18 baby blocks.... need help. Quote:
 
June 18th, 2012, 02:25 PM  #6  
Member Joined: Jun 2012 From: UK Posts: 39 Thanks: 0  Re: 18 baby blocks.... need help. Quote:
 
June 18th, 2012, 02:33 PM  #7 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,406 Thanks: 859 Math Focus: Elementary mathematics and beyond  Re: 18 baby blocks.... need help.
Yes, that is for one letter specified before the drawing begins. The probability for all three the same, the letter being determined by the first pick, would be 1/136.


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