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 June 7th, 2012, 04:33 PM #1 Newbie   Joined: May 2012 Posts: 21 Thanks: 0 solve the equation 1/3r^(3/2)+3/2r^(1/2)=0 and 1/5t^(1/3)+5/2t^(-2/3)=0 I need help with these 2 questions. Thanks. June 7th, 2012, 05:31 PM #2 Global Moderator   Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4 Re: solve the equation I could guess as to what the equations look like, but won't. Could you either: 1) Visit the link in my profile for LATEX (preferred), or 2) at least add some parenthesis to clear things up? June 7th, 2012, 06:19 PM #3 Senior Member   Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: solve the equation I feel lucky...I'll guess you mean: 1.) 1/(3r^(3/2)) + 3/(2r^(1/2))=0 We see that the least common denominator is , so multiply through by this expression to get: 2.) 1/(5t^(1/3)) + 5/(2t^(-2/3))=0 Rewrite with positive exponents: We see that the least common denominator is , so multiply through by this expression to get: June 7th, 2012, 06:48 PM #4 Global Moderator   Joined: Dec 2006 Posts: 20,931 Thanks: 2207 For the questions as posted, r = 0 and t = -25/2. June 7th, 2012, 07:14 PM   #5
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Re: solve the equation

Quote:
 Originally Posted by ahereicome 1/3r^(3/2)+3/2r^(1/2)=0 and 1/5t^(1/3)+5/2t^(-2/3)=0 I need help with these 2 questions. Thanks.
I'm sorry guys; next time, I will add parentheses, and the LATEX is kinda hard to use lol, but here it's after I edited:
1) (1/3r^(3/2))+(3/2r^(1/2))=0

2) (1/5t^(1/3))+(5/2t^(-2/3))=0

skipjack actually got the answers for me; it's the same as on the textbook, but I want the steps, thanks!!!! June 7th, 2012, 07:37 PM #6 Senior Member   Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: solve the equation The parentheses you added are unnecessary as they do not change the interpretation of the equations. To make it more clear, you could type: 1.) (1/3)r^(3/2)+(3/2)r^(1/2)=0 Factor: If we assume the terms in the original equation represent real values, then we discard the negative root, and are left with: 2.) (1/5)t^(1/3)+(5/2)t^(-2/3)=0 Note: hence we may multiply through by to get: Tags equation, solve Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Shamieh Algebra 6 May 21st, 2013 09:46 PM mmmmxxx Algebra 3 September 4th, 2012 06:22 PM boomer029 Algebra 8 March 17th, 2012 05:09 PM ishoothigh Algebra 1 December 14th, 2011 08:09 AM sagelady Calculus 2 July 24th, 2011 08:35 PM

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