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May 13th, 2012, 02:12 PM  #1 
Newbie Joined: Mar 2012 Posts: 12 Thanks: 0  Poisson Distribution  find mean
Hi, have this problem i need to solve. The number of clients that go to a store per hour uses a Poisson distribution. It's known that the probability of arriving 15 customers in an hour is 0.031 and, also the probability of arriving 16 customers in an hour is 0.062. What is the mean of arriving customers per hour in the store. I'm having trouble interpreting the problem. I don't know what is given. If it's P(X=15)=0,031, or P(X <=15)=0,031 or P(X >= 15)=0,031 Any help appreciated. Thanks. 
May 13th, 2012, 04:29 PM  #2  
Senior Member Joined: Apr 2011 From: USA Posts: 782 Thanks: 1  Re: Poisson Distribution  find mean Quote:
So we're saying (Now if you need help with the equation, you'll need someone else cause I have no idea how to solve for the mu. We always just used the charts. I looked on the chart, but never found 15 & 16 together matching. So unless you have a much bigger chart, I'm assuming you're using the equation.)  
May 13th, 2012, 06:10 PM  #3  
Senior Member Joined: Dec 2011 Posts: 277 Thanks: 1  Re: Poisson Distribution  find mean Quote:
 
May 13th, 2012, 06:12 PM  #4 
Senior Member Joined: Dec 2011 Posts: 277 Thanks: 1  Re: Poisson Distribution  find mean
First, note that the probability of We're told that (1) and (2) and we need to solve for . From 2, we can rewrite the equation to get (3) Substitute (1) into (3) yields Edit: Ah! You didn't ask for this (how to solve for the mean)! 
May 14th, 2012, 12:35 PM  #5 
Newbie Joined: Mar 2012 Posts: 12 Thanks: 0  Re: Poisson Distribution  find mean
Yes, i just wanted help interpreting the problem... but thanks.

May 15th, 2012, 12:10 PM  #6  
Senior Member Joined: Apr 2011 From: USA Posts: 782 Thanks: 1  Re: Poisson Distribution  find mean Quote:
 
May 15th, 2012, 08:29 PM  #7  
Senior Member Joined: Dec 2011 Posts: 277 Thanks: 1  Re: Poisson Distribution  find mean Quote:
 

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