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April 13th, 2012, 05:11 AM   #1
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logarithmic expansion

Hi;
I need to expand log4(x^2 + 9)/log4(x^2 - 6x + 8)^2/3. the 4 is tha base.




2/3log4(x^2 + 9) / 2/3log4(x^2 -6x + 8)

2/3log4x^2 + 9 - 2/3log4x^2 - 6x +8 This is where I not sure with the quadratic
I guess you just expand it

giving

2/2log4x^2 - 2/3log4(x - 2) + 2/3log4(x + 4)

and thats it I think.
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April 13th, 2012, 05:43 AM   #2
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Re: loarithmic expansion

Hello, anthonye!

A strange problem . . . not much can be done with it.
Are you sure it says "expand"?


Quote:








Edit: corrected the omission of the 2/3 power.
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April 13th, 2012, 05:49 AM   #3
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Re: loarithmic expansion

Surely the division becomes subtraction and you missed the 2/3 off.
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April 13th, 2012, 09:35 AM   #4
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Re: loarithmic expansion

Hello again, anthonye!

Quote:
Surely the division becomes subtraction.[color=beige] . [/color][color=blue]No, it doesn't![/color]






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April 13th, 2012, 10:40 AM   #5
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Re: logarithmic expansion

Ok thanks Soroban.
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