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April 12th, 2012, 02:17 AM  #1 
Newbie Joined: Apr 2012 Posts: 2 Thanks: 0  How many solutions to an equation
Hi folks, I am trying to help my son with his Maths revision but too many years and brain cells have been and gone. Can someone help to explain how we should approach this problem? How many solutions does the equation (4sinx  5root5)(sin x+1)=0 have in the interval 0?x<2? Thanks 
April 12th, 2012, 04:19 AM  #2  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Re: How many solutions to an equation Hello, raycol1970! Quote:  
April 13th, 2012, 04:19 AM  #3 
Newbie Joined: Apr 2012 Posts: 2 Thanks: 0  Re: How many solutions to an equation
Soraban  thank you ever so much!  listen really sorry I made a mistake in the question it should be just root5 and not 5root5  really sorry for this...

April 14th, 2012, 02:03 PM  #4  
Newbie Joined: Apr 2012 From: Padua, Italy Posts: 15 Thanks: 0  Re: How many solutions to an equation Quote:
 

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