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 April 8th, 2012, 01:38 PM #1 Senior Member   Joined: Mar 2012 Posts: 111 Thanks: 0 Absolute Value question |8-x|>0 is the answer: A. -8-x B. -8+x C. 8-x D. 8+x I put B as the answer. Is this correct?
 April 8th, 2012, 03:29 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs Re: Absolute Value question You may geometrically interpret the statement as all numbers x such that the distance between x and 8 is greater than zero, that is all real numbers except 8. We have two cases to consider: $8-x=>0\:\therefore\<8" /> $x-8=>0\:\therefore\>8" /> or we may simply choose to write: $8-x\ne0\:\therefore\\ne8" /> Thus x is in: $$$-\infty,\,\cup\,\(8,\infty$$" />
 April 9th, 2012, 08:59 PM #3 Newbie   Joined: Apr 2012 Posts: 10 Thanks: 0 Re: Absolute Value question I too have a question regarding absolute values. solve algebraically: x = |4x-1| are 1/3 and 1/5 correct?
 April 9th, 2012, 09:26 PM #4 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs Re: Absolute Value question You should begin your own topic, but just please do that in the future... You have two cases to consider: 1.) $x=4x-1$ $3x=1$ $x=\frac{1}{3}$ 2.) $x=-(4x-1)$ $x=-4x+1$ $5x=1$ $x=\frac{1}{5}$ You are correct.

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