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April 4th, 2012, 03:39 PM   #1
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Mixture Problem

What would my equation(s) be to solve this mixture story problem?

How much 12% Na2SO4 and pure water must be mixed to produce 22.8 gallons of a mixture that is 7% sodium sulfate?

I started with: Let x = the # of gallons of 12% Na2SO4
And Let y = the # of gallons of 100% water or should it be Let 22.8-x = the # of gallons of 100% water needed?
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April 4th, 2012, 03:49 PM   #2
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Re: Mixture Problem

I would start by finding the amount in gallons of pure sodium sulfate we need:



Now we want to find how many gallons x of the 12% mixture contains that amount:





So, we need 13.3 gallons of the 12% sodium sulfate and 22.8 - 13.3 = 9.5 gallons of water.

We could also simply the process somewhat (combine the two steps into one) and state:



and then the amount of water is 22.8 - 13.3 = 9.5.
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April 4th, 2012, 07:38 PM   #3
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Re: Mixture Problem

Hello, Kimmysmiles0!

Quote:

Since we are adding pure water, we will consider the amount of water at each stage.


















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