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 March 24th, 2012, 10:22 AM #1 Newbie   Joined: Mar 2009 Posts: 13 Thanks: 0 General Math Question Hi Guys, I simply wanted to ask, I have a large file that I want to download the size of 4,375,272 at the speed of 160kb/sec. How can i find out how long it will take in HH:MM:SS? I have tried the following: $a = 4,375,272$b = 160kb/sec $totalsecs =$a * $b = 700043520$totalmins =\$totalsecs / 60 = 11667392 ... not sure where to go from here? Can somebody help me find a way for me to find out how long it will tak to download?
 March 24th, 2012, 11:43 AM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs Re: General Math Question Let t be the download time. Assuming the file size is in bytes: $t=\frac{4375272\text{ B}}{160\cdot2^{10}\text{ \frac{B}{s}}}=\frac{546909}{20480}\:\text{s}\appro x26.7\text{ s}$
 March 24th, 2012, 11:51 AM #3 Newbie   Joined: Mar 2009 Posts: 13 Thanks: 0 Re: General Math Question Can you explain your method?
 March 24th, 2012, 01:37 PM #4 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs Re: General Math Question total bytes = (bytes per time)(total time) thus: total time = (total bytes)/(bytes per time) It is mathematically equivalent to asking how long will it take to travel a certain distance at a certain speed: time = distance/speed

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