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March 4th, 2012, 08:31 PM  #1 
Member Joined: Feb 2012 Posts: 97 Thanks: 0  Add and Subtract Indicated Okay, I know that I'm suppose to multiply the top and bottom so that the denominator is alike, but it's not. Ugh, I broke the bottom down to be in the first column and this is where I'm lost, the "r" . . . I've tried making both denominatiors 2r(r+6) by multiplying 2(r+6) just lost

March 4th, 2012, 08:39 PM  #2  
Global Moderator Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4  Re: Add and Subtract Indicated Quote:
You'll also need to multiply the first term by r/r  
March 4th, 2012, 08:43 PM  #3 
Member Joined: Feb 2012 Posts: 97 Thanks: 0  Re: Add and Subtract Indicated
It's still not coming out the right answer, 
March 4th, 2012, 08:55 PM  #4 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038  Re: Add and Subtract Indicated
What's the "right answer"? I get: 3(r  4)  2r(r+6) ?? 
March 4th, 2012, 08:57 PM  #5 
Member Joined: Feb 2012 Posts: 97 Thanks: 0  Re: Add and Subtract Indicated
That's the answer. But what do you have on the second denominator when you're multiplying?

March 4th, 2012, 09:12 PM  #6 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038  Re: Add and Subtract Indicated
Not sure what you're asking, HB, but here's my steps: 5 / (2r + 12)  1 / r = [5r  1(2r + 12)] / [r(2r + 12)] = (5r  2r  12) / (2r^2 + 12r) = (3r  12) / [2r(r + 6)] = [3(r  4)] / [2r(r + 6)] Like: a/b  c/d = (ad  bc) / bd Hope that helps instead of confuses Being 7/10 baldheaded, I musy say I'm jealous of your Afro 
March 4th, 2012, 11:25 PM  #7 
Member Joined: Feb 2012 Posts: 97 Thanks: 0  Re: Add and Subtract Indicated Thanks, I'll give you some hair.


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