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 r-soy February 28th, 2012 05:43 PM

How can I do the calculation here

Hi

Resolution = Vfs/2^n

Resolution = 3
Vfs = 2 V

find n

how I can find the n ... ?

 MarkFL February 28th, 2012 06:04 PM

Re: How can I do the calculation here

If I am interpreting this correctly, you have:

$2^{1-n}=3$

$1-n=\frac{\log(3)}{\log(2)}$

$n=1-\frac{\log(3)}{\log(2)}\approx-0.5849625007211561$

 r-soy February 28th, 2012 06:22 PM

Re: How can I do the calculation here

thanks

 r-soy February 28th, 2012 07:16 PM

Re: How can I do the calculation here

If

Resolution = 3
Vfs = 5V

n = 1 - (lpg(3) / log(5))

is correct ?

 MarkFL February 28th, 2012 07:27 PM

Re: How can I do the calculation here

No, that isn't correct.

We can solve for n in general:

$R=\frac{V_{fs}}{2^n}$

$2^n=\frac{V_{fs}}{R}$

$n=\frac{\log$$\frac{V_{fs}}{R}$$}{\log(2)}$

Now, when given values for $R$ and $V_{fs}$ just plug them into the above formula for n.

 r-soy February 29th, 2012 01:35 AM

Re: How can I do the calculation here

OK ..

thanks

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