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 February 9th, 2012, 08:18 AM #1 Member   Joined: Nov 2011 Posts: 72 Thanks: 0 Algebra Question ((lf2-l2)(a2*e2))/l2 = - ((lf1 - l1)(a1*e1))/l1) Solve for lf2 and lf1
February 9th, 2012, 08:51 AM   #2
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Re: Algebra Question

Quote:
 Originally Posted by hatchelhoff ((lf2-l2)(a2*e2))/l2 = - ((lf1 - l1)(a1*e1))/l1) Solve for lf2 and lf1
You're given:
$\frac{(lf_2-l_2)(a_2e_2)}{l_2}=-\frac{(lf_1-l_2)(a_1e_1)}{l_1}$
Solving for $lf_2$:
$(lf_2-l_2)(a_2e_2)=-\frac{(lf_1-l_2)(a_1e_1)l_2}{l_1}$
$\Rightarrow lf_2-l_2=-\frac{(lf_1-l_2)(a_1e_1)l_2}{l_1(a_2e_2)}$
$\Rightarrow lf_2=l_2-\frac{(lf_1-l_2)(a_1e_1)l_2}{l_1(a_2e_2)}$

Showe some work for $lf_1$.

 February 10th, 2012, 03:47 AM #3 Member   Joined: Nov 2011 Posts: 72 Thanks: 0 Re: Algebra Question Thanks Siron but I meant can you get lf1 and lf2 on the same side of the equation.
 February 11th, 2012, 05:28 AM #4 Global Moderator   Joined: Dec 2006 Posts: 20,746 Thanks: 2133 What difficulty are you having with that and can you correct the typo in the equation you gave?

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