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February 9th, 2012, 08:18 AM   #1
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Algebra Question

((lf2-l2)(a2*e2))/l2 = - ((lf1 - l1)(a1*e1))/l1)
Solve for lf2 and lf1
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February 9th, 2012, 08:51 AM   #2
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Re: Algebra Question

Quote:
Originally Posted by hatchelhoff
((lf2-l2)(a2*e2))/l2 = - ((lf1 - l1)(a1*e1))/l1)
Solve for lf2 and lf1
You're given:

Solving for :




Showe some work for .
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February 10th, 2012, 03:47 AM   #3
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Re: Algebra Question

Thanks Siron
but I meant can you get lf1 and lf2 on the same side of the equation.
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February 11th, 2012, 05:28 AM   #4
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What difficulty are you having with that and can you correct the typo in the equation you gave?
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