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 January 27th, 2012, 01:41 AM #1 Member   Joined: Jan 2012 Posts: 33 Thanks: 0 Small problem Moving van rentals: Davis Truck Rentals will rent a moving van for $15.75/day plus$0.35 per mile. Bertz Van Rentals will rent the same van for $25/day plus$0.30 per mile. How many miles m must the van be driven to make the cost at Bertz a better deal? $15.75\text{ day}\,+\,0.35\text{ mi}\,=\,x\text{ mi}$ $15.75\text{ day}\,\div\,0.35x\,=\,45\text{ mi}$ $25\tex{ day}\,+\,0.30\text{ mi}\,=\,x\text{ mi}$ $25\text{ day}\,\div\,0.30x\,=\,83\text{ mi}$ $45\,+\,83\,=\,128$ $m\,\gt\,128$ Right ?
 January 27th, 2012, 01:59 AM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,879 Thanks: 1087 Math Focus: Elementary mathematics and beyond Re: Small problem Is there any mention of a time period, in days? If not, I'm not sure that I understand the question; the value of paying 0.05 dollars less per mile will change depending on how many days the van is rented for. If the intended period of rental is one day, the van must be driven over 185 miles.
January 27th, 2012, 02:44 AM   #3
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Re: Small problem

Quote:
 Originally Posted by thinkfast Moving van rentals: Davis Truck Rentals will rent a moving van for $15.75/day plus$0.35 per mile. Bertz Van Rentals will rent the same van for $25/day plus$0.30 per mile. How many miles m must the van be driven to make the cost at Bertz a better deal? $15.75\text{ day}\,+\,0.35\text{ mi}\,=\,x\text{ mi}$ $15.75\text{ day}\,\div\,0.35x\,=\,45\text{ mi}$ $25\tex{ day}\,+\,0.30\text{ mi}\,=\,x\text{ mi}$ $25\text{ day}\,\div\,0.30x\,=\,83\text{ mi}$ $45\,+\,83\,=\,128$ $m\,\gt\,128$ Right ?
Wrong. Why divide daily cost by per mile cost?
Set them equal:
25.00 + .30m = 15.75 + .35m
Solve for m.

 January 27th, 2012, 05:23 AM #4 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,879 Thanks: 1087 Math Focus: Elementary mathematics and beyond Re: Small problem @thinkfast: for a new problem please post in a new topic. I have split your latest post in this topic into a new topic, found here.

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