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 December 26th, 2011, 04:36 PM #1 Newbie   Joined: Jul 2010 Posts: 18 Thanks: 0 Laws of Exponents How would I simplify this equation? $\left[\frac{(-4x^4y^3z)^2(3xyz^5)^3}{6x^2yz}\right]^2$
 December 26th, 2011, 04:45 PM #2 Math Team   Joined: Nov 2010 From: Greece, Thessaloniki Posts: 1,990 Thanks: 133 Math Focus: pre pre pre pre pre pre pre pre pre pre pre pre calculus Re: Laws of Exponents [color=#000000]$\frac{(-4x^4 y^3 z)^2 (3xyz^5)^3}{6x^2 y z }=\frac{(4x^4 y^3 z)^2 (3xyz^5)^3}{6x^2 y z }=\frac{16x^8 y^6z^2 27 x^3 y^3 z^{15}}{6x^2 y z}=72 x^9 y^8 z^{16}$ so the answer is $\left(72 x^9 y^8 z^{16}\right)^{2}=72^{2}x^{18}y^{16}z^{32}$.[/color]
 December 26th, 2011, 06:33 PM #3 Newbie   Joined: Jul 2010 Posts: 18 Thanks: 0 Re: Laws of Exponents Thank you very much for your help

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