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December 26th, 2011, 12:36 AM   #1
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new math antonymy, please help me to confirm

Please check the attached file; I don't know how to show. Thanks.
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December 26th, 2011, 01:43 AM   #2
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Re: new math antonymy, please help me to confirm

What is that: a puzzle?!
And what is your question?
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December 26th, 2011, 02:04 AM   #3
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A: there is no rule that x^(limit f(x)) = limit(x^f(x)) unless x = 1.

B: if the limit exists, its value is 0 (because |x| < 1) or 1 (because x = 1).
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December 26th, 2011, 03:58 PM   #4
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Thanks jack. My friend's researched on these two problems at least 20 years, now his body is worse. He is not a really math scientist but just freedom by his interesting. I saw him is so pity. May be his question is very easy and it is not deserve him to research for all his life.
What he did say is that our 'limit' with problem, so we can not use 'existing limit theory' to explain. How do you think that? Is he crazy?
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