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December 11th, 2011, 05:59 AM  #1 
Newbie Joined: Dec 2011 Posts: 1 Thanks: 0  Damn confusing.... 72 matches are played in a tournament. Find the number of teams if each team plays 1 match with other teams.

December 11th, 2011, 06:59 AM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,934 Thanks: 1128 Math Focus: Elementary mathematics and beyond  Re: Damn confusing....
Number of matches, M = n(n  1)/2, where n is the number of teams, with each team playing each other team exactly once. Solving this for M = 72 doesn't give an integer result for n, so I doubt the problem is stated correctly. If M = 78, n = 13; if M = 66, n = 12.

December 11th, 2011, 07:36 AM  #3 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,412 Thanks: 1024  Re: Damn confusing....
Deepz, you could have at least tried with fewer teams, to "see" how it works: 2: A,B : AB ; 1 3: A,B,C : AB,AC,BC ; 3 4: A,B,C,D : AB,AC,AD,BC,BD,CD ; 6 5: A,B,C,D,E : AB,AC,AD,AE,BC,BD,BE,CD,CE,DE ; 10 ... 1,3,6,10,15,21,28,36,45,55,66,78... Perhaps one team got drunk with 6 games to go and got locked up for disturbing the peace 
December 11th, 2011, 09:26 AM  #4  
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361  Re: Damn confusing....
Perhaps, there is a returnmatch; AB and BA.. EDIT (actually not, Quote:
 

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