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December 11th, 2011, 05:59 AM   #1
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Damn confusing....

72 matches are played in a tournament. Find the number of teams if each team plays 1 match with other teams.
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December 11th, 2011, 06:59 AM   #2
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Re: Damn confusing....

Number of matches, M = n(n - 1)/2, where n is the number of teams, with each team playing each other team exactly once. Solving this for M = 72 doesn't give an integer result for n, so I doubt the problem is stated correctly. If M = 78, n = 13; if M = 66, n = 12.
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December 11th, 2011, 07:36 AM   #3
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Re: Damn confusing....

Deepz, you could have at least tried with fewer teams, to "see" how it works:
2: A,B : AB ; 1
3: A,B,C : AB,AC,BC ; 3
4: A,B,C,D : AB,AC,AD,BC,BD,CD ; 6
5: A,B,C,D,E : AB,AC,AD,AE,BC,BD,BE,CD,CE,DE ; 10
...
1,3,6,10,15,21,28,36,45,55,66,78...

Perhaps one team got drunk with 6 games to go and got locked up for disturbing the peace
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December 11th, 2011, 09:26 AM   #4
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Re: Damn confusing....

Perhaps, there is a returnmatch; AB and BA..

EDIT (actually not,
Quote:
Originally Posted by deepz007
plays 1 match with other teams.
)
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