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November 27th, 2011, 07:25 PM  #1 
Senior Member Joined: Nov 2011 Posts: 101 Thanks: 0  another weird problem... help
solve the system, answer with an ordered triple: 2x5y+4z3w=7 x+6y+7zw=14 3x2y+w=5 4x+y8z=3 What the heck is this? I am at college algebra matrix section, but these numbers are impossibly complicated for this level of algebra. So I put this in box matrix box and do rref= 2 5 4 3 7 1 6 7 1 14 3 2 0 1 5 4 1 8 0 3 I get 1 0 0 0 (55/379) 0 1 0 0 (411/379) 0 0 1 0 (211/379) 0 0 0 1 (1238/379) so x = (55/379), y= (411/379), z= (221/379), w= (1238/379). When I use calculator and plug these #s in, I get right answer. but is this even right? Am I understanding question wrong or is this suppose to be some crazy problem that's supposed to get this kind of complicated # and can only be done by calculator? help.. 
November 27th, 2011, 07:34 PM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs  Re: another weird problem... help
Those values agree with what I get too. I suspect you are either to use calculator/computer or Gaussian elimination. 
November 27th, 2011, 08:23 PM  #3 
Senior Member Joined: Nov 2011 Posts: 101 Thanks: 0  Re: another weird problem... help
thx. You are my lifesaver. Am I suppose to put answer in { (x,y,z,w) } format or something else?

November 27th, 2011, 08:54 PM  #4 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs  Re: another weird problem... help
It says to answer with an ordered triple, but there are 4 variables, so I would use an ordered quadruple (w,x,y,z).

November 29th, 2011, 11:45 AM  #5  
Global Moderator Joined: Dec 2006 Posts: 20,469 Thanks: 2038  Quote:
For example, the equations 2x  5y + 4z  3w = 77 x + 6y + 7z  w = 34 3x  2y + w = 5 4x + y  8z = 3 are similar and the corresponding values of w, x, y and z are all integers.  

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