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November 22nd, 2011, 05:55 PM   #1
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Find the equation of the line through P that cuts the line?

Find the equation of the line through P(-1,0,1) that
cuts the line r=(3,2,1)+t(1,2,2) at right-angles at Q
Also find the length PQ and the equation of the plane containing the two lines.

Given that a=(3,2,1) and b=(1,-2,-4) are the position vectors of the points P and Q respectively, find

a)the equation of the plane passing through Q and the perpendicular to PQ
b)the distance from the point (-1,1,1)to the plane in (a)
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November 23rd, 2011, 03:19 PM   #2
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Re: Find the equation of the line through P that cuts the li

Hello, luketapis!

Here's the first one . . .


Quote:

[color=beige]. . . [/color]3,\,2,\,1)\,+\,t(1,\,2,\,2)\text{ at right angles at }Q." />







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[color=beige]. . . . [/color]





[color=beige]. . [/color]




[color=beige]. . [/color]




Quote:
(b) Find the length









Quote:
(c) Find the equation of the plane containing the two lines.






[color=beige]. . [/color]






[color=beige]. . [/color]

[color=beige]. . [/color]

[color=beige]. . [/color]

[color=beige]. . [/color]

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