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November 10th, 2011, 08:29 AM   #1
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Log help for a not so good math student!

Can someone help me answer these log equations...

Use the properties of logarithms to write the expression as a sum, difference, and/or constant multiple of logarithms(assume all variables are positive)

1.) Log(10) Y/2

2.) Log(6) z-3


And these as well

Write the expression as the logarithm of a single quantity.

1.) 1/3 log(3) 5x

2.) ln(x-2)-ln(x+2)


Could you please do it step by step because I am confused...Thank you very much for your help!!
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November 10th, 2011, 08:45 AM   #2
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Re: Log help for a not so good math student!

What are the "properties of logs" ??
I know the answer, and believe that You should ask yourself this question.

log(ab) = log(a) + log(b) is one property.
log(6) = log(3) + log(2) is an example of this property.

If you can name the properties and explain them in plain English, you will be able to do these problems.
Also, should it read "z - 3", or "z^-3" ?
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November 10th, 2011, 08:56 AM   #3
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Re: Log help for a not so good math student!

Quote:
Originally Posted by The Chaz
What are the "properties of logs" ??
I know the answer, and believe that You should ask yourself this question.

log(ab) = log(a) + log(b) is one property.
log(6) = log(3) + log(2) is an example of this property.

If you can name the properties and explain them in plain English, you will be able to do these problems.
Also, should it read "z - 3", or "z^-3" ?

z^-3(-3 exponent)


Thanks for the info and I will give it a shot...

For the first one...is it log(3) 1/3+x^5?
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November 10th, 2011, 11:14 AM   #4
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Re: Log help for a not so good math student!

Can anyone help me out

These 2 (Write the expression as the logarithm of a single quantity)

1.) 1/3 log(3) 5x

2.) ln(x-2)-ln(x+2)



1.)Log(10) Y/2

2.) Log(6) z^-3


I'm not being lazy...I legitimately don't understand how to do them and how to get the correct answer.
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November 10th, 2011, 11:35 AM   #5
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Re: Log help for a not so good math student!

Chaz is this one of the correct answers?

For log(6)z^-3

I got 1-3log(6)z
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November 18th, 2011, 09:59 AM   #6
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Where did the "1" come from? You need to use the rule that
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