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November 3rd, 2011, 03:27 PM   #1
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solving logarithmic equations

The problem is (x^2)e^4x + (7x)e^4x - e^4x
I took e^4x out and I'm left with
e^4x(x^2+7x-1)

How do I solve from here? I can't figure out how to factor to get my smaller and larger values.
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November 3rd, 2011, 04:02 PM   #2
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If you were asked to factor the expression, you've already done enough. As there are no logarithms in the expression, why does the topic title refer to logarithmic equations?
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November 3rd, 2011, 04:12 PM   #3
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Re: solving logarithmic equations

Because that is the section of the chapter we are in. We are supposed to use logs to solve I think. We have to have two answers: a smaller value and larger value.
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November 3rd, 2011, 05:00 PM   #4
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Re: solving logarithmic equations

Quote:
Originally Posted by hannah2329
The problem is (x^2)e^4x + (7x)e^4x - e^4x
But that's NOT an equation.
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November 3rd, 2011, 05:20 PM   #5
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Re: solving logarithmic equations

It is supposed to be equal to zero. Sorry, I forgot to put it.
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November 3rd, 2011, 11:42 PM   #6
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Re: solving logarithmic equations

The solutions of an equation of the form :
f(x) g(x) = 0
are the solutions of f(x) =0 and the solutions of g(x) = 0
insofar as solution(s) exist.
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November 4th, 2011, 01:38 AM   #7
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Re: solving logarithmic equations

It must be noted that has no solutions.



Use quadratic formula.
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