October 17th, 2011, 01:20 AM  #1 
Senior Member Joined: Sep 2011 Posts: 140 Thanks: 0  complex number
Okay I have a question, well actually I solved it, but I don't know if it's correct. It would be great if you guys could correct my mistakes if any are made, Thank you. So we have two complex numbers, and the modulus of is and the modulus of the argument of and the argument of hence find the smallest positive integer m,n for since 0 is an integer, the smallest m and n is 0. 
October 17th, 2011, 02:50 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 17,720 Thanks: 1359 
Zero isn't a positive integer. You seem to have "i" missing from the definition of 
October 17th, 2011, 02:57 AM  #3 
Senior Member Joined: Sep 2011 Posts: 140 Thanks: 0  Re: complex number
but argument and modulus is correct right?

October 17th, 2011, 03:14 PM  #4 
Global Moderator Joined: Dec 2006 Posts: 17,720 Thanks: 1359 
Without knowing the correct version of the problem, it's impossible to tell.

October 18th, 2011, 05:09 AM  #5 
Senior Member Joined: Sep 2011 Posts: 140 Thanks: 0  Re: complex number
Yea, I made a typo, there is an i in the . So having that said, is the mod and arg correct? Also, what would be m and n? 
October 18th, 2011, 05:38 AM  #6 
Global Moderator Joined: Dec 2006 Posts: 17,720 Thanks: 1359 
Where is the i in the ?

October 18th, 2011, 05:45 AM  #7 
Senior Member Joined: Sep 2011 Posts: 140 Thanks: 0  Re: complex number
square root 3

October 18th, 2011, 06:37 AM  #8 
Global Moderator Joined: Dec 2006 Posts: 17,720 Thanks: 1359  Re: complex number
You found the modulus of each number correctly. For equality, m = n/2. The arguments were nearly right. If the complex numbers are equal, m needs to be a multiple of 3. What else is needed? 

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