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 January 8th, 2008, 01:19 PM #1 Newbie   Joined: Jan 2008 Posts: 5 Thanks: 0 Converting cartesian coordinates to polar coordinates Hey everybody, i have a function in relation to x,y and z. how can i convert this function in a polar coordinate system depending on r and two angles? thanks!
January 8th, 2008, 01:26 PM   #2
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Re: Converting cartesian coordinates to polar coordinates

Quote:
 Originally Posted by Eppo Hey everybody, i have a function in relation to x,y and z. how can i convert this function in a polar coordinate system depending on r and two angles? thanks!
x=rcosucosv
y=rsinucosv
z=rsinv

r nonnegative, |u|<=pi, |v|<=pi/2

 January 9th, 2008, 04:37 AM #3 Newbie   Joined: Jan 2008 Posts: 5 Thanks: 0 ok thanks so my new function is F(rcosucosv,rsinucosv,rsinv) ? What happens if i have an equation, e.g. F(x,y,z) = a Do I have to translate the a too? Or do i just write: F(rcosucosv,rsinucosv,rsinv) = a
January 9th, 2008, 07:25 AM   #4
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Quote:
 Originally Posted by Eppo Do I have to translate the a too?
No.

 January 9th, 2008, 09:03 AM #5 Newbie   Joined: Jan 2008 Posts: 5 Thanks: 0 yep ok i got that. so what about derivatives? the problem is, i dont know the actual function, it is a differential equation. So there is just a * F"(x,y,z) + b * F(x,y,z) = 0 I translate this function to polar coordinates, what changes for the derivative?
January 9th, 2008, 01:35 PM   #6
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Quote:
 Originally Posted by Eppo yep ok i got that. so what about derivatives? the problem is, i dont know the actual function, it is a differential equation. So there is just a * F"(x,y,z) + b * F(x,y,z) = 0 I translate this function to polar coordinates, what changes for the derivative?
You have F''(x,y,z). What is the variable of the derivative? The prime notation makes sense only for functions of one variable.

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