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January 8th, 2008, 02:19 PM  #1 
Newbie Joined: Jan 2008 Posts: 5 Thanks: 0  Converting cartesian coordinates to polar coordinates
Hey everybody, i have a function in relation to x,y and z. how can i convert this function in a polar coordinate system depending on r and two angles? thanks! 
January 8th, 2008, 02:26 PM  #2  
Global Moderator Joined: May 2007 Posts: 6,402 Thanks: 546  Re: Converting cartesian coordinates to polar coordinates Quote:
y=rsinucosv z=rsinv r nonnegative, u<=pi, v<=pi/2  
January 9th, 2008, 05:37 AM  #3 
Newbie Joined: Jan 2008 Posts: 5 Thanks: 0 
ok thanks so my new function is F(rcosucosv,rsinucosv,rsinv) ? What happens if i have an equation, e.g. F(x,y,z) = a Do I have to translate the a too? Or do i just write: F(rcosucosv,rsinucosv,rsinv) = a 
January 9th, 2008, 08:25 AM  #4  
Global Moderator Joined: Dec 2006 Posts: 18,250 Thanks: 1439  Quote:
 
January 9th, 2008, 10:03 AM  #5 
Newbie Joined: Jan 2008 Posts: 5 Thanks: 0 
yep ok i got that. so what about derivatives? the problem is, i dont know the actual function, it is a differential equation. So there is just a * F"(x,y,z) + b * F(x,y,z) = 0 I translate this function to polar coordinates, what changes for the derivative? 
January 9th, 2008, 02:35 PM  #6  
Global Moderator Joined: May 2007 Posts: 6,402 Thanks: 546  Quote:
 

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cartesian, converting, coordinates, polar 
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