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December 30th, 2007, 02:17 AM   #1
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basic mathematics question on %s

Hi, i have a question which will probably be very easy for you guys, but i dont know the answer.
Please show your workings....

I have a budget of 500,000 and 3 things to spend it on, A, B & C
And we assume that A will cost 9 per hour, B costs 14 and C 15 per hour.

How many hours each can we spend on each if we want
205 of the hours to be bought be A, 20% by C and 60% by C.

Many thanks.
Scott
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December 30th, 2007, 08:55 AM   #2
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I assume you mean that you buy some multiple of 20 hours of A, 20 hours of B and 60 hours of C. Those quantities would cost 20×9 + 20×14 + 60×15, i.e., 1360. Since your budget is 500,000, the multiple should be 500,000/1360, i.e., 367.647..., or 367.6 if you have to buy whole numbers of hours. Using 367.6, you buy 367.6×20 hours of A, i.e., 7352 hours of A, 7352 hours of B, and 22056 hours of C, using 499936 of your budget.
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December 31st, 2007, 01:47 AM   #3
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Thanks, very helpful.
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