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December 20th, 2007, 02:46 PM   #1
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Simplying an Algebraic function

Hi there,
It would be great if someone could simply this algebraic function for me, I tried few times, but I'm not getting the same answer as the textbook. Thanks in advance.

Quote:
 ((-3x^2y^3) - (3x^6/y))/y^6
This is answer they have in the textbook:

Quote:
 (-3x^2(y^4 + x^4)) / y^7 December 20th, 2007, 03:45 PM #2 Senior Member   Joined: Apr 2007 Posts: 2,140 Thanks: 0 ((-3x^2y^3) - (3x^6/y)) / (y^6) = ((-3x^2y^3) - (3x^6/y))(y) / (y^6)(y) = ((-3x^2y^4) - (3x^6)) / (y^7) = (-3x^2(y^4+x^4)) / (y^7) December 20th, 2007, 05:37 PM   #3
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Quote:
 Originally Posted by johnny ((-3x^2y^3) - (3x^6/y)) / (y^6) = ((-3x^2y^3) - (3x^6/y))(y) / (y^6)(y) = ((-3x^2y^4) - (3x^6)) / (y^7) = (-3x^2(y^4+x^4)) / (y^7)
johnny, you are the man! Thanks alot for solving it out for me. You wouldn't believe but I spent more than 1 hour tryina figure out how they got the answer. One thing that I'm still not too sure about is that, why did u have to multiply both sides, (-3x^2y^3) AND (3x^6/y) by "y"? what is wrong with only multiplying 3x^6/y by "y". Hope to hear from you soon. Once again, Thank you for your help !  December 20th, 2007, 05:56 PM #4 Senior Member   Joined: Apr 2007 Posts: 2,140 Thanks: 0 Multiplying 3x^6/y by y is important. In order to do this, we have to multiply ((-3x^2y^3) - (3x^6/y)) by y. I'll generalize this below. In algebraic operations, we can say that (a - b)(c) = ac - bc. So, at ((-3x^2y^3) - (3x^6/y)) / (y^6), if we want to get rid of the denominator y of 3x^6/y, we have to multiply by y, and to make the algebra easier, multiply the whole parenthesis part by y, and you can get rid of denominator y, and that's pretty much it. Let me know if you have question. December 20th, 2007, 06:41 PM #5 Newbie   Joined: Dec 2007 Posts: 5 Thanks: 0 it makes sense, johnny. Thank you !  Tags algebraic, function, simplying Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Confused dude Algebra 28 January 30th, 2013 03:08 PM bilano99 Algebra 4 June 8th, 2012 07:43 AM brian890 Trigonometry 3 November 25th, 2011 09:43 PM jaspertml Calculus 1 January 5th, 2010 03:44 PM imcutenfresa Calculus 3 September 15th, 2009 07:58 PM

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