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 Algebra Pre-Algebra and Basic Algebra Math Forum

 August 13th, 2011, 11:49 AM #1 Senior Member   Joined: Jul 2009 Posts: 136 Thanks: 0 mean proportions Hello all! I can find the mean proportion of ab and bc (it was the first, and simplest, problem) as b squared = ac or b = the sq. root of ac. Whoops! I just saw that the text offers the answer as b sq. x root of ac.... i.e., b ac with the square root bracket, no = sign. And the next problem is find the mean proportion of 8a squared and 2b squared (only the a and the b are "squared"). I'm hung up on whether I should put this into an equation as 8/a squared = 2/b squared which would result in (I think) 8b sq = 2 a sq Am I on the right track or way off? I think I'm off track here! If you have a clue, then it would be appreciated. Thanks! August 14th, 2011, 05:53 AM #2 Senior Member   Joined: Jul 2009 Posts: 136 Thanks: 0 Re: mean proportions--I got it! OK, I'm a little slow but I finally got it. ab to bc means ab/x = x/bc; thus, ac (b squared) = x squared, take the square root and one has x = (b)the square root of ac. And the other problem follows similarly.... 8asquared/x = x/2bsq.; thus x squared = 16 a squared b squared, take the square root and the result is x = 4ab. Voila! Tags proportions Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post anthonyhark Art 7 February 2nd, 2014 04:58 PM Mpigs89 Elementary Math 3 November 25th, 2013 08:31 PM darocker077 Algebra 6 February 10th, 2013 10:42 PM MathematicallyObtuse Algebra 3 February 7th, 2012 06:13 AM 3ztt Algebra 2 February 9th, 2009 09:26 AM

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