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 August 3rd, 2011, 03:47 PM #1 Newbie   Joined: Aug 2011 Posts: 7 Thanks: 0 Algebraic Expression Problem If g(x)=2x+5(3x-2), find: a. g(1) b. g(0) c. g(-3) d. g(x) = 6, x= e. g(x)=-2, x= Please help, I need his by tomorrow. Or at least please point me in the correct direction. Thanks!
 August 3rd, 2011, 03:55 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,912 Thanks: 1110 Math Focus: Elementary mathematics and beyond Re: Algebraic Expression Problem a. If g(x) = 2x + 5(3x - 2), g(1) = 2(1) + 5(3(1) - 2) = 2 + 5(3 - 2) = 2 + 5(1) = 7. d. If g(x) = 6, 6 = 2x + 5(3x - 2) = 2x + 15x - 10 = 17x - 10, x = (6 + 10)/17 = 16/17.
 August 3rd, 2011, 04:06 PM #3 Newbie   Joined: Aug 2011 Posts: 7 Thanks: 0 Re: Algebraic Expression Problem You find it out by filling in X's with the anser in parentheses by the F.
 August 3rd, 2011, 04:25 PM #4 Newbie   Joined: Aug 2011 Posts: 7 Thanks: 0 Re: Algebraic Expression Problem Please help me answer this. I need it by tomorrow. :/
August 3rd, 2011, 04:40 PM   #5
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Re: Algebraic Expression Problem

Quote:
 Originally Posted by trapezoids You find it out by filling in X's with the anser in parentheses by the F.
Yes. If it were me, I would simplify g(x):

$g(x)=2x+5(3x-2)=2x+15x-10=17x-10$

Thus:

a) g(1) = 17(1) - 10 = 7
b) g(0) = 17(0) - 10 = -10

etc.

d) 17x - 10 = 6

17x = 16

x = 16/17

 August 3rd, 2011, 05:09 PM #6 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,912 Thanks: 1110 Math Focus: Elementary mathematics and beyond Re: Algebraic Expression Problem [color=#00AA00]MarkFL[/color] has the right idea. I should have looked at simplifying g(x), but it seemed simple enough at the time!
 August 3rd, 2011, 07:22 PM #7 Member   Joined: May 2011 From: West Virginia Posts: 44 Thanks: 0 Re: Algebraic Expression Problem Yeah, just like they were saying, just plug in your values, where the x variables are present.

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