
Algebra PreAlgebra and Basic Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
July 14th, 2011, 03:39 PM  #1 
Newbie Joined: Jul 2011 Posts: 3 Thanks: 0  Arithmetic Progression
I have been trying to resolve this = n/2(2*2+(n1)*2)=n(n+1) and this is equal to 79*80 I got stuck when I got to 2n^2 +2n=12,640 
July 14th, 2011, 03:47 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,933 Thanks: 2207 
By inspection, 2(n  79)(n + 80).

July 15th, 2011, 12:37 PM  #3 
Global Moderator Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4  Re: Arithmetic Progression
Kodwo, From the looks of it, you knew (?) the following: n*(n + 1) = 79*80 n*(n + 1) = 79*(79 + 1) If that is the case, then there really is no easier case of "inspection". You can tell that if we replaced the "n"s on the left with "79", then there would be a true statement. The approach that is less magical would be to solve the quadratic equation that you listed: 2n^2 + 2n  12640 = 0 n^2 + n  6320 = 0 Then you are looking for factors of 6320 that differ by 1. That in itself could be a chore for some, so you could resort to the quadratic formula. In either case, you will get the provided solution. 
July 16th, 2011, 09:50 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 20,933 Thanks: 2207 
A chore? The square root of 6320 is clearly slightly less than 80, so 79*80 would be the first thing to try.


Tags 
arithmetic, progression 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
arithmetic progression  will.i.am1  Algebra  14  May 29th, 2013 06:27 AM 
Arithmetic progression  Algebra  2  April 5th, 2012 09:46 PM  
Arithmetic Progression  Trafford99  Algebra  7  February 28th, 2012 03:07 PM 
arithmetic progression  panky  Algebra  4  November 17th, 2011 07:05 AM 
Arithmetic Progression help!  Francis410  Algebra  1  March 22nd, 2011 07:02 AM 