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 July 4th, 2011, 01:58 PM #1 Newbie   Joined: Jul 2011 Posts: 20 Thanks: 0 solve algebraically I have not taken a math course in over a year and was wondering if someone could help me to recall a few things. I need to solve for y: 2m= (3y-4)/(5-x) For m: 2m= (3y-4)/(5-x) for x: 2m= (3y-4)/(5-x) Can someone help me understand how to do this? Thank you!
 July 4th, 2011, 02:12 PM #2 Senior Member   Joined: Sep 2010 Posts: 101 Thanks: 0 Re: solve algebraically If it asks you to solve let's say for x, that means that on left side of equality you need to have x: (x=...). So out of that equation you have to express x. Same is for m or y. Does this help?
 July 4th, 2011, 03:06 PM #3 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: solve algebraically I'll do the first part, and see if you can apply the technique to the other two parts. Solve $2m=\frac{3y-4}{5-x}$ for y. We wish to isolate y one one side of the equation and everything else on the other side. So the first thing we need to do is get rid of the denominator on the right side by multiplying both sides by that denominator so that it will calcel out on the right side: $2m(5-x)=\frac{3y-4}{5-x}(5-x)$ Now divide out or cancel the factor common to the denominator and numerator on the right: $2m(5-x)=3y-4$ Now we need to remove the 4 being subtracted on the right by adding 4 to both sides: $2m(5-x)+4=3y-4+4$ Since -4 + 4 = 0, and a + 0 = a, we may now write: $2m(5-x)+4=3y$ Now we need to remove the coefficient of y which is 3 by dividing both sides by 3: $\frac{2m(5-x)+4}{3}=\frac{3y}{3}=\frac{3}{3}y=y$ Thus, we find: $y=\frac{2m(5-x)+4}{3}$

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