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December 6th, 2007, 09:04 PM   #1
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alternate quadratic formula


I have a question that's been bugging me for quite a while...

Is there an alternate quadratic formula?

I know the standard one...

However, I know there has to be another one!

I used to be actively involved in Kumon, a rigorous Japanese Mathematics program. While in Kumon, I remember learning this alternate quadratic formula. I am no longer in the Kumon program, so I don't remember this alternate quadratic formula.

What I do remember is that it was shorter and simpler.

Does anybody know this alternate quadratic formula??? If anyone could please tell me that would be great... it would make my math homework A LOT easier.

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December 7th, 2007, 05:43 AM   #2
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Any such formula would have to give the same answers, so you can manipulate the formula into whatever kind of formula you like. But in the end all formulas will be of the form

A +/- B where A = -1/2 b/a and B = sqrt(b^2/4 - ac)/a

though they may look different.
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December 9th, 2007, 01:45 PM   #3
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If a formula is a solution to an equation and is able to give ALL the solutions to the equation, then it is THE ONLY such formula. It would be contradictory otherwise.
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December 18th, 2007, 07:04 AM   #4
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x = 2c/(-b ?(b - 4ac)) (provided a and c are non-zero)
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January 15th, 2012, 09:23 AM   #5
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Re: alternate quadratic formula

I go to kumon. I think the answer you're looking for is the one that you can do provided that b in ax2 + bx + c is replaced by an even number (2b). It becomes (-b?(b^2-ac))/a.
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January 15th, 2012, 09:26 AM   #6
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Re: alternate quadratic formula

Perhaps it is this.
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February 6th, 2012, 06:51 PM   #7
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Re: alternate quadratic formula


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June 23rd, 2016, 01:41 AM   #8
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I used to visit kumon. I had the same question as i forgot it too

check the attachment
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File Type: png Screen Shot 2016-06-23 at 12.37.15 PM.png (13.6 KB, 11 views)
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