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 December 6th, 2007, 09:04 PM #1 Newbie   Joined: Dec 2007 Posts: 1 Thanks: 0 alternate quadratic formula Hi, I have a question that's been bugging me for quite a while... Is there an alternate quadratic formula? I know the standard one... However, I know there has to be another one! I used to be actively involved in Kumon, a rigorous Japanese Mathematics program. While in Kumon, I remember learning this alternate quadratic formula. I am no longer in the Kumon program, so I don't remember this alternate quadratic formula. What I do remember is that it was shorter and simpler. Does anybody know this alternate quadratic formula??? If anyone could please tell me that would be great... it would make my math homework A LOT easier. Thanks!!!!
 December 7th, 2007, 05:43 AM #2 Global Moderator     Joined: Nov 2006 From: UTC -5 Posts: 16,046 Thanks: 937 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms Any such formula would have to give the same answers, so you can manipulate the formula into whatever kind of formula you like. But in the end all formulas will be of the form A +/- B where A = -1/2 b/a and B = sqrt(b^2/4 - ac)/a though they may look different.
 December 9th, 2007, 01:45 PM #3 Senior Member   Joined: May 2007 Posts: 402 Thanks: 0 If a formula is a solution to an equation and is able to give ALL the solutions to the equation, then it is THE ONLY such formula. It would be contradictory otherwise.
 December 18th, 2007, 07:04 AM #4 Global Moderator   Joined: Dec 2006 Posts: 18,686 Thanks: 1522 x = 2c/(-b ± ?(b² - 4ac)) (provided a and c are non-zero)
 January 15th, 2012, 09:23 AM #5 Newbie   Joined: Jan 2012 Posts: 1 Thanks: 0 Re: alternate quadratic formula I go to kumon. I think the answer you're looking for is the one that you can do provided that b in ax2 + bx + c is replaced by an even number (2b). It becomes (-b±?(b^2-ac))/a.
 January 15th, 2012, 09:26 AM #6 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,757 Thanks: 1008 Math Focus: Elementary mathematics and beyond Re: alternate quadratic formula Perhaps it is this.
 February 6th, 2012, 06:51 PM #7 Math Team     Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233 Re: alternate quadratic formula If $ax^2= bx + c$ then $x= \frac{b \pm\sqrt {b^2 + 4ac}}{2a}$
June 23rd, 2016, 01:41 AM   #8
Newbie

Joined: Jun 2016
From: Kenya

Posts: 1
Thanks: 0

I used to visit kumon. I had the same question as i forgot it too

check the attachment
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# how to shorten quadratic expressions

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