December 27th, 2006, 06:19 AM  #1 
Member Joined: Nov 2006 From: BIG APPLE Posts: 63 Thanks: 0  correct
find the domain of the following function: f(x) = 1 / x^2  16 so domain = ( x #£ ¶R  x ? 0, x^2 ? 16 ) YES? 
December 27th, 2006, 07:55 AM  #2 
Senior Member Joined: Nov 2006 From: I'm a figment of my own imagination :? Posts: 848 Thanks: 0 
A function of this type is undefined when the denominator is equal to zero. If you meant the function to be as written, then its domain is all real numbers except x=0. If, however, you meant 1/(x^2  16), then the function is defined for all real numbers except x=4 and x=4 because x^2  16 factors as (x + 4)(x  4).


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