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December 27th, 2006, 06:19 AM   #1
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correct

find the domain of the following function:

f(x) = 1 / x^2 - 16

so

domain = ( x #£ ¶R | x ? 0, x^2 ? 16 )

YES?
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December 27th, 2006, 07:55 AM   #2
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A function of this type is undefined when the denominator is equal to zero. If you meant the function to be as written, then its domain is all real numbers except x=0. If, however, you meant 1/(x^2 - 16), then the function is defined for all real numbers except x=4 and x=-4 because x^2 - 16 factors as (x + 4)(x - 4).
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