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 May 2nd, 2011, 10:12 AM #1 Member   Joined: Feb 2011 Posts: 49 Thanks: 0 Laws of Logarithms Simplify. 4^log base 2 (2^ log base 2 5)
 May 2nd, 2011, 12:03 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Laws of Logarithms We have: $4^{\log_2$$2^{\log_2\(5$$}\)}$ Use $\log_a$$b^c$$=c\log_a b$ to write $4^{\log_2$$5$$\log_2$$2$$}$ Use $\log_a a=1$ to write: $4^{\log_2$$5$$}$ Use $4=2^2$ to write: $$$2^2$$^{\log_2$$5$$}$ Use $$$a^b$$^c=a^{bc}$ to write: $2^{2\log_2$$5$$}=2^{\log_2$$25$$}$ Use $a^{\log_a$$b$$}=b$ to write: $25$
 May 2nd, 2011, 02:45 PM #3 Senior Member   Joined: Apr 2007 Posts: 2,140 Thanks: 0
 May 3rd, 2011, 03:34 AM #4 Member   Joined: Feb 2011 Posts: 49 Thanks: 0 Re: Laws of Logarithms Thanks for all the help.

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